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How much oil to add to a gallon of fuel to get a specific percentage
This question comes up from time to time, and it's a bit of a head scratcher. For anybody who wants to know how much oil to add to a gallon to get a specific percentage of oil in the final mix (which will be more than a gallon), here's a formula.
A= ounces of additional oil L = original lube percentage expressed in a decimal. ( 17% is .17) F = final lube percentage expressed as a decimal. 128L + A = F (128 + A) Or more simply, A = F (128 + A)  128L If you have a gallon (128 oz) of fuel with 17% lube, how much oil do you add to get 20% oil in your final mix, which will be more than a gallon after you add the oil? A = .2 (128 + A) (128 x .17) A = 25.6 + .2A 21.76 A = 3.84 + .2A .8A = 3.84 A = 4.8 Add 4.8 ounces to get 132.8 ounces of fuel with a total of 20% oil. 






Great formula!
Not to be pedantic, but just as an additional: For the people working in metric, they would use litres and ml, and the formula would be a lot easier to work with if it is rewritten to this form: (1F)A=FL or even simpler : A=(FL)/(1F) For the same values of initial L=17%, desired F=20% 0,8 x A=0,20,17 or: A=(0,20,17)/0,8 A= 0.0375 or in plain language, 3,75% of the original total volume, to be added in oil. That way it does not matter if you have a batch of a quart, 2,5 litres, a barrel or whatever amount of fuel you have.... (4,8 ounces is 0.0375 gallon: 0,0375 x 128=4.8) As a check: 17% fuel would contain (duh!) 170 ml oil 1,0375 L of fuel containing 207,5 ml of oil: (207,5/1037,5)=0,2... Check! 

Last edited by Brutus1967; Oct 28, 2016 at 05:15 PM.
Reason: Stupid writing error, some additional things




So what you both are saying is;
If I have 128 ounces of 17% fuel then 83% of it is methanol, so 128*.83=106.24 of methanol in that gallon. But I want that 106.24 of methanol to be 80% of the total fuel (ie 20% oil) so 106.24\.8=132.8 ounces of fuel. So I need to add 132.8128=4.8 ounces of oil to make the 132.8 total? Sounds about right. Dave H 





I also use my method if I want convert a three (or more) component fuel to something else eg a gallon of 17% oil, 10% nitro fuel to 17% synthetic, 3% castor, 15% nitro fuel.
It also works if I want to end up with a different volume as well. Eg if you wanted to convert that original gallon of 17% to 2 gallons of 20%. I just find it easier this way, but I'm sure a formula could be worked out as well. Dave H 

Last edited by gerryndennis; Oct 29, 2016 at 02:19 AM.











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