Mar 01, 2011, 10:52 AM
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United States, OH, Bradford
Joined Jun 2005
3,440 Posts
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Depends on the plane. The wing rod has to be strong enugh for the loads applied to it. For an open class airplane that has to be tolerant of winch launching, that means being able to handle about 300 pounds of winch line tension.
That means each wing is carrying about 150 pounds, centered about 40% of the way out from the root, so on a 10 ft. span airplane that's a bending moment at the root of about 3600 in-lbs. If you have a 1/2 inch diameter joiner, stress = Mc/I, where M is the moment, c is the distance from the neutral axis to the outermost fiber (so half the diameter, or 1/4" in this case), and I is the section modulus. For a round rod:
I = (Pi * D^4)/64 which in this case is 0.00307
Plugging all of that into our equation, we get:
stress = 3600 * .25 / .00307 = 293,000 PSI
which would require a hardened alloy steel with a hardness of about 55 Rc or better, which means heat-treated tool steel. Some of the ejector pins in the previous posts are that strong, some are not. Music wire, particularly piano wire, is that strong and hard (which is why it can put nice little dents in tool-steel diagonal cutters), but good luck trying to find some 1/2" piano wire!
If all you plan to do is high-start or electric, you can get away with less.
It all depends on what you plan to do. If you are going to apply a certain load to a part, then that part must be strong enough to handle that load.
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