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USA, MO, O'Fallon
Joined Dec 2003
1,924 Posts
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Dave,
I have read the notes already. Perhaps I did not make myself as clear as I should. One of the posts I read recently mentioned charging an not empty pack as a possible problem (overcharging?) and I thought that my charger was supposed to prevent that. Do you discharge your battteries at all, or do you slap them back ing the charger once the motor starts to slow down? My ESP did not have a low voltage cut out, and so my 'clues' to the end of flight were duration and losing lift. |
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USA, MO, O'Fallon
Joined Dec 2003
1,924 Posts
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Jim takes the prize.
I attempted to charge a 2 cell pack on the 3 cell setting. Operator error coupled with immature technology (the charger really should be able to detect proper voltage for something this important) resulted in a $500 lesson. CHECK YOUR JUMPERS!!!!! Man do I feel stupid now. Poor too. Jim, thank you very much for figuring out what went wrong. |
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Arlington,VA USA
Joined Jan 2001
1,852 Posts
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Thats unfortunate. I'm suprised it is not smart.
I really like my Apache 1500 charger. Very simple. Has the following features: Jumper selectable 1-4 cells 250,700,1200, and 1500ma charge rates (1C) Auto-trickle down for last phase of charge (puts more Mah into cells) Low-voltage destination-battery detect (This would have saved you a destroyed pack and scary situation) High-voltage destination-battery detect (will not charge an already-charged pack) Low/High voltage source 12V battery check (will not run down your charger ba |
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Walled Lake, MI, USA
Joined Feb 2000
11,182 Posts
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Martimer, I've been so focused on trying to make sure that you understood the fundamentals of Li-polys before using them again that I forgot to say that I am sorry about your loss and pleased that no one was injured. This is really the most important thing to be concerned about.
I'm glad you've read the sticky and understand a lot of the basics about Li cells. This kind of knowledge will help you from making some mistakes. But you will still make mistakes, just like the rest of us, as we humans just can't seem to nail that elusive perfection thing. You may have picked up the idea about fully discharging Li packs by reading a message about someone putting a fully charged 3-cell pack on an automatic charger, and the automatic charger interpreting the pack as a partially charged 4-cell pack. This is one of the dangers of some automatic chargers. This does not mean that you should try to discharge a Li pack as far as you can. Never do that! It's always best to ask lots of questions as you are doing now. There are many people here who have a lot of knowledge about Li cells that can help you with anything that you don't fully understand. Blueprints, if you have 1000mAh cells, you can connect as many of them in series as you want, and you will still have a 1000mAh pack. The only thing that happens as you add cells in series is that the voltage increases with the addition of each cell. With a 1000mAh pack, you should be able to draw 1000mA (or 1A) for an hour. If the cells are connected in parallel, the voltage remains the same but the overall capacity of the pack increases, i.e. 1000mAh + 1000mAh + 1000mAh = 3000mAh for three Li cells in parallel. If you connect three 3-cell series packs in parallel (3s3p), you will have three times the voltage and three times the capacity. |
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Space Coast
Joined Oct 2000
18,596 Posts
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Quote:
Consider this. 1. The plane needs 50W to fly right. 2. Cells are lipo 1000mah 3. 2s pack yields 7.4V nominally. To obtain 50W, the pack needs to supply 6.76A. 4. 1000mah/6760ma = 0.147hr x 60min/hr = 8.88 min flying time. 5. 3s pack yields 11.1V nominally. To obtain 50W to fly right, pack needs to only supply 4.5A. 6. 1000mah/4500ma = 0.22hr x 60min/hr = 13.3 min flying time. Cell capacity still is 1000mah but flying time increases 33%, whcih just happens to relate to the increase in the number of 1000mah cells. ![]() hoppy |
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Walled Lake, MI, USA
Joined Feb 2000
11,182 Posts
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Hoppy, I figured he wanted the simple version. But since you got into the advanced course, would it not be true that the added weight of the third cell would have an effect on the flying time so that it would not be increased by a full 33%?
And that's not even getting into the space-time continuum factor .....
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