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We can measure the idle currentdirectly. In theory also the internal resistance
could be measured directly, but all our formulas are quite sensitive to
, so it has to be as exact as possible, which is difficult to measure because the values are so low. We choose another way and calculate the values for
and
by solving a set of simultaneous equations. (for the math guys, this is the fun part!) We start with two copies of formula (8), one for each measurement we have made for one motor:
(8-1)
(8-2)
We get two equations, each containing the same two unknown values. to eliminatefrom (8-1) we convert (8-2) by dividing both sides by the terms in the parentheses into:
(8-3)![]()
...and replacein (8-1) by the right side of (8-3):
(9-1)
Now we sort the values until we have an equation for:
step 1: multiply both sides by
(9-2)
step 2: eliminating the parentheses:
(9-3)
step 3: sorting terms with and without:
(9-4)
step 4: puttingoutside the parentheses:
(9-5)![]()
step 5: dividing both sides by:
(9-6)
...and we finally have calculated (not measured)! we put this
into formula (8-1) to get
:
(8-4)
Now we have measured and calculated all the significant motor constants:,
, and
, which we can use in turn to calculate all the values of equations (2) - (8). To do this we just have to measure
and
in each operation point, means, with each combination of motor, battery, gearbox and prop that we are interested in!
The value of, which is calculated through the "back door" will, when used in our formulas, exactly deliver the voltage, current, and rpm that we put into our formulas in the beginning. So a lot of possible measuring errors will be compensated.
Formula (10) did also not fall from heaven. I will show you how it is developed. At first we had formula (4):
(4)
...that we multiply out and get:
Still (4)
to find the current at which maximum power is achieved we build the first derivation ofto
:
(14)
will be zero at the maximum power because at lower current the power rises, so the first derivation is positive, and at higher current the power goes down, so the first derivation is negative. Since the power will change continuously when variating the current, we know that the first derivation has to cross the zero line exactly at the point of maximum power. We use this:
(14)
We addon both sides:
(14-1)![]()
We divide byon both sides and get:
(14-2)![]()
That is identical to formula (10), which was to prove.
Now that we start to like mathematics :-) we will go on and show how to develop formula (11). We start with formula (7):
(7)
That is (by multiplying out and reducing) the same as:
(7)
We build the first derivation ofto
and set it to zero, as above:
(15)
We addon both sides:
(15-1)![]()
Multiply by:
(15-2)
Divide by:
(15-3)
Building the square root:
(15-4)
That is identical to formula (11), which is also proven now.
The interested reader who was willing to follow me that far will be able to prove formula (12) also! Tip: eliminatein formula (7) by using formula (11), multiply out and reduce! Have fun!
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