12V Resistor Charge Lead, does anyone know how to make one?

[mitch]

hi all from australia :)
what i need to know is the resistence and wattage used in these leads
i have all the parts and wish to make instead off buy one
these are the ones used off a 12volt car battery to a 7.2/8.4 volt 1500MAH
battery
thanks for reading
regards
m



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[Dean]

Using ohms law (V=IR)

It looks like a 1 ohm resistor would get your around 5 amps of
current.

The only problem here, is power dissipated = Voltage drop* amps.
That means it dissipates ~25 watts while it allows only 5 amps
through. You will need a pretty big resistor for this...That's a fair
amount of power being dissipated.

10 10ohm resistors in parallel will get you 1 ohm also, and you can
easily find 10ohm resistors that can handle 2 watts each.

When the pack starts warming up, it's done charging. Do NOT
overcharge it. And please, double check my work with an ammeter
before you blow up your battery pack :-)

-Dean

On Sun, 16 Mar 2003 01:30:29 +0800, "mitch" <lmcomms.nospam@nw.com.au>
wrote:

>hi all from australia :)
>what i need to know is the resistence and wattage used in these leads
>i have all the parts and wish to make instead off buy one
>these are the ones used off a 12volt car battery to a 7.2/8.4 volt 1500MAH
>battery
>thanks for reading
>regards
>m
>
>
>
>---
>Outgoing mail is certified Virus Free.
>Checked by AVG anti-virus system (http://www.grisoft.com).
>Version: 6.0.459 / Virus Database: 258 - Release Date: 25/02/2003
>

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