PDA

View Full Version : Swept back LE = ? Dihedral


Dereck
Jan 23, 2003, 02:52 PM
Okay, you aerodynamically inclined wizzards out there. Been through all my complicated books, and this has me stumped.

The model is a new Own Design, 52" span, rest of numbers bear close resemblance to a scaled down FAI pattern ship - long moment, 25% tailplane, big verticals and the tailplane is pretty low with respective to the wing and TL.
The wing LE has 9 degrees of rear sweep, TE is "straight" (I fancied the look of it from many, many doodles). Right now, have 1.5 degrees of dihedral in the common old style, measured on the wing centreline from the front (slight taper from root to tip due to reduced chord, wing % thickness is identical from root to tip).

I know that sweep back has the effect of effectively increasing dihedral - anyone out there offer any ideas, opinions WHY's as to whether or not that 9 deg sweep will add much to my regular dihedral?

TIA folks

Regards

Dereck

DNA
Jan 23, 2003, 07:17 PM
http://www.djaerotech.com/dj_askjd/dj_questions/sweepdihedral.html

Ollie
Jan 23, 2003, 07:48 PM
The sweep angle is not determined by the leading edge or trailing edge. It is the 25% chord line's angle to a perpendicular to the center line that determines the wing's sweep angle.
See: http://www.b2streamlines.com/ and down load a PDF docuent on effective dihedral.

Dereck
Jan 24, 2003, 10:06 AM
Thank you for the inputs - after due consideration, I shall build and fly the little beggar and let folk know what happens (if it flies good ) or fix it on the quiet if it don't ;) The 25% chord line sweeps a tad less than the LE, of course, as the TE is straight.

The decision to use this planform must have cost me an inch in pencil lead and the backs of several used envelopes. I should never get technical, my head starts to hurt ;)

Regards

Dereck