Connector Question

[mathinstrument]

How many amps can the deans connector take?

When taking into consideration about the size of connectors to use, is it the amps or the watts?
Because Amps X volts = watts.
If a connector can take 50A, does it mean 50A @ any voltage?
10V X 50A = 500w
42V X 50A = 2100w!!!

So which is which?

[CANTZ506]

I can't answer your first question, sorry.

About parameters for a connector, the main is the current it can stand, and mainly is limited by the section area of the contacts.

The voltage is not an issue, as it's assumed that is more great than the used voltage; it's the break voltage that could arch between the contacts.

The power mostly interested in a connector is the power lost as heat across the junction male-female; if the contact is poor, a greater resistance is in series with the circuit and a greater voltage's drop rises.
The power lost in heat is Wlost= Current x Voltage's drop. This power, when very high, could melt the insulation between the contacts.

[mike50]

As CANTZ506 said, the power lost to heating the connector is Power = Current x VoltageDrop. The voltage drop is: VoltageDrop = Current x ConnectorResistance.

So the Power lost is:

Power = Current x Current x ConnectorResistance. (W = I^2 * R)

Pretty much it is independent of voltage, as long as it isn't so high that it arcs across the contacts.

Mike